Arifmetik progressiya

9-sinf Matematika

B -variant

1.Funksiyaning aniqlash sohasini toping. y=3x-x³

A)(-;-3)(0;3) B)(-;-3(0;3 C)0;3) D)(-;3)(3;) E)0;)

2.Quyidagi funksiyalardan qaysi biri juft?

(x-8)² x⁴+x²+1 7x

A)y= B)y=2x*|x|+5 C)y= D)y= 3 2 x²-9

3.Funksiyaning o’sish oralig’ini aniqlang: y=(x-1)²

A)(-;1)(1;) B) (-;-1)(-1;) C) (-;) D) (-;0)(0;) E) (0;)

4 .Tenglamani yeching. x²-12=x

A)x₁=3,x₂=4 B)x=4 C)x=3 D)x₁=2,x₂=3 E)x₁=1,x₂=5

5 .Tenglamani yeching.x-2=3x-6

A)2 B)3 C)1 D)0 E)-2

6.sin /2+sin 3 /2 ni hisoblang.

A)0 B)1/2 C)-1 D)2/2 E)1

7.Agar tg *cos o bo’lsa,  burchak qaysi chorakka tegishli?

A)2;3 B)3;4 C)1;2 D)1;3 E)1;4

8.ifodani soddalashtiring:cos(3/2-)*tg (-)

A)-sin*tg  B)cos*tg  C)sin*tg  D) -cos*tg  E) sin*ctg 

9.Sin 2010⁰ ni hisoblang.

A)1/2 B)-3/2 C) 3/2 D)1 E)-1/2

10. Cos²(+x)+ Cos²(/2+x) ifodani soddalashtiring.

A) B)cos x C)sin²x D)2 E)1

11. sin²- cos²+cos⁴

 ni soddalashtiring.

cos²- sin²+sin⁴

A)tg⁴ B)tg² C) ctg⁴ D) 1/2tg² E) 2ctg²

12.Agar cos 2=1/2 bo’lsa ,cos²  ni hisoblang.

A)1/2 B)3/2 С)3/4 D)3/8 E)1/8

13.Sin =3/5 va /2 bo’lsa, tg  ni toping.

A)-4/5 B)-3/4 С)3/4 D) -3/5 E) 3/5

14.ctg2-ctg ni soddalashtiring.

1 1 1 1 1

A) B) C) -  D)  E)- 

Sin2 cos2 Sin2 Sin2 sin²

15. Sin =-3/5 bo’lsa, cos2 ni hisoblang.

A)1/25 B)-7/25 С)2/5 D)3/5 E) 7/25

16.Bir nuqta orqali nechta tekislik o’tadi?

A)1 B)2 C)3 D)4 E)istalgancha

17.Kub uchun nechta simmetriya tekisligi mavjud?
A)8 B)9 C)7 D)10 E)6

18.Mn kesma  tekislikda yotmaydi, MM₁,NN₁,va M₁,N₁nuqtalarda  tekisliknikesib o’tadi.Agar MM₁=12, M₁,N₁=5,NN₁=24 bo’lsa, MN ni toping.

A)26 B)13 C)14 D)15 E)16

19.Kubning bir uchidan chiqqan yoqlarining dioganallari juftliklari orasidagi burchak necha gradus?

A)60⁰ B)45⁰ C)9⁰ D)30₀ E)75⁰

20.Nechta nuqta orqali 1ta tekislik o’tadi?

A)4 B)3 C)5 D)1 E)cheksiz ko’p

21.Tekislikka tushirilgan og’ma bilan perpendikulyar orasidagi burchak 60⁰ . og’maning uzunligi 203. Perpendikulyarning uzunligini toping.

A)10 B)40 C)103 D)53 E)20

22.To’g’ri chiziq va tekislik orasidagi burchak qanday burchak bo’ladi?

A)to’g’ri B)o’tkir C)o’tmas D)yoyiq E)vertical

23.Ikki to’g’ri chiziq necha xil holatda bo’ladi?

A)1 B)2 C)3 D)4 E)5

24.AA₁ BB₁ A₁, B₁ nuqtalar  tekislikda yotadi. AA₁=9sm, A₁B₁=8sm BB₁=15sm Abni toping.

A)5 B)10 C)12 D)8 E)17

25.Berilgan nuqtadan tekislikka ikkita og’ma va perpendikulyar tushirildi. Og’malarning proyeksiyalari 27 va 15 ga teng, hamda ulardan biri ikkinchisidan 6 ga uzun bo’lsa, perpendikulyarlarning uzunligini toping.

A)30 B)39 C)45 D)33 E)36

9-sinf Matematika

A-variant

x-3

1.Funksiyaning aniqlanish sohasini toping: y=

x²-4

A)(-2;) B)(-;) C)(-;-2) D)(-;-2)(-2;) E) (-;-2)(-2;2)(2;)

2.Quyidagi funksiyalardan qaysi biri toq?

7x 3x⁴+x2 2x x(x-8)

A)y= B)y= C)y=|x+3|-6x D)y= E)y=

X+3 8 x²-9 5x+3

3.Funksiyaning kamayish oralig’ini aniqlang: y=3

x

A)(-;) B) (-;0)(0;) C) (-;3)(3;) D) (-;-3)(-3;)

4.Tenglamaning musbat ildizini toping: x^1/2=5

A)5 B)25 C)125 D) 5 E)³5

5.Tenglamani yeching: x+4-x-1=1

A)4 B)3 C)-5 D)-4 E)5

6.5sin 90⁰+2cos0⁰-2sin270⁰+10cos 180⁰ni hisoblang.

A)-3 B)-6 C)-1 D)9 E)19

3 

7.Sin=  bo’lsa cosni toping.

1. 2

A)-  2/3 B) 2/3 C)2/3 D) 2/3 E)1

8.Ifodani soddalashtiring: cos*tg-2sin

A)sin B)cos C)-sin D)-cos E)tg

9.Cos(-45⁰)+sin315⁰+tg(-855⁰)ni hisoblang.

A)0 B) 2-1 C)1+3 D)-1 E)1

10.cos2+cos(/2-)*sin

 ni soddalashtiring

sin(/2+)

A)cos B)2 sin C)-cos D)tg E)-sin

11. sin3 cos3

 --  ni soddalashtiring.

sin cos

A)2cos B)2 C)2 sin D)1 E)0,5

12. tg=1/2 bo’lsa tg 2--?

A)5/3 B)4/3 С)3/4 D)3/5 E)1

13.Agar cos 2=1/2 bo’lsa, cos² ni hisoblang.

A)1 B) 3/2 C)3/4 D)3/8 E)1/8

1 4.Sin75⁰-sin15⁰ni hisoblang.
A) 2/2 B) 3/2 C) 2 D)-2 E) -2/2

15.Tenglamani yechin: cos (/2-x)=1

A)/2+2n, nZ B)+n, nZ C)0 D)1 E)/2+n, nZ

16.Ikki nuqta orqali nechta tekislik o’tadi?

A)1 B)1 C)3 D)4 E)istalgancha

17.Asosi kvadrat bo’lgan to’g’ri burchakli parallelepiped uchun nechta simmetriya tekisligi mavjud?

A)9 B)7 C)3 D)5 E)4

18.AB kesma  tekislikni O nuqtada kesadi. AA₁,BB₁.Agar AA!=6, BB1=2, ob1=1,5 bo’lsa, Abni toping.

A)10 B)5 C)15 D)20 E)25

19. Kubning qirrasi a bo’lsa, kub dioganalini toping.

A)a2 B)a3 C)2a2 D)2a3 E)6a3

20.Nechta holatda yagona tekislik o’tkazish mumkin?

A)2 B)3 C)4 D)5 E)cheksiz ko’p

21.Tekislikka o’tkazilgan perpendikulyar bilan og’ma orasidagi burchak 30⁰, perpendikulyarninguzunligi esa10 ga teng.Og’maning uzunligini toping.

A)20 B)103 C)203 D)20/3 E)203

22.Kubning dioganallari va asos tekisligiorasidagi burchakni toping.

A)60⁰ B)30⁰ C)arcos 2/3 D)arcsin3/4 E)arctg ½

23.To’g’ri chiziq va tekislik necha xil holatda bo’ladi?

A)1 B)2 C)3 D)4 E)5

24.AA₁, BB₁ A₁,B₁ nuqtalar  tekislikda yotadi.AA1=10sm, BB1=30sm, A1B1=15sm ABni toping.

A)25 B)20 C)10 D)15 E)20,5

25.Nuqtadan tekislikka ikkita og’ma o’tkazilgan.Agar og’malar 1:2ga teng nisbatda bo’lib,ularning proyeksiyalari 1 va 7 ga teng bo’lsa, og’malarning uzunligini toping.

A)2;4 B)3;6 C)4;8 D)5;10 E)1;2

В вариант

1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25
E	D	B	B	E	C	A	C	E	A	B	B	C	A	A	E	D	A	B	C	D	C	C	A	C

А Вариант

1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25
A	C	C	B	A	A	C	C	E	E	A	C	A	C	E	E	B	B	A	B	C	B	C	B	E